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-.7t^2+49t=0
We add all the numbers together, and all the variables
-0.7t^2+49t=0
a = -0.7; b = 49; c = 0;
Δ = b2-4ac
Δ = 492-4·(-0.7)·0
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-49}{2*-0.7}=\frac{-98}{-1.4} =+70 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+49}{2*-0.7}=\frac{0}{-1.4} =0 $
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